Paths to Math: John Urschel
Paths to Math: John Urschel

This problem, we are given that c of x equals to 300 minus 35 times x, raised to the power 6 over 1 minus 5 times x, raised to the power 6 minus 95 times x, the whole divided by x, squared plus 75 times x, minus 18 point And in this problem we are asked to find out the value of the limit limit, extends to infinity c of x, so let us perform limit x tends to infinity term by term, starting with the first term. We have limit, extends to infinity 300 point, since this is a constant. We get the same constant itself. Next, we have limit, extends to infinity 35 times x, raised to the power 6. The whole divided by 1 minus 5 times x, raised to the power 6. This can be rewritten as limit extends to infinity 35 times x, raised to the power 6. The whole divided by factoring out x, raised to the power 6. We have 1 over x, raised to the power 6 minus 5 x, raise to the power 6 and x, raised to the power 6 get canceled, and now let us substitute the limit. So we have 35 over limit, extends to infinity of 1. Raised 1 over x, raised to the power. 6 is 0, so we get 0 minus 5. Simplifying this. We have 35 over negative…

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